(2x^2+4x-576)=0

Solution for (2x^2+4x-576)=0 equation:

(2x^2+4x-576)=0

We get rid of parentheses

2x^2+4x-576=0

a = 2; b = 4; c = -576;
Δ = b2-4ac
Δ = 42-4·2·(-576)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-68}{2*2}=\frac{-72}{4}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+68}{2*2}=\frac{64}{4}
=16
$